Question

a sample of 5 litre gas in open vessel is taken at 300K temperature and it is heated upto 450K , then what fraction of gas will escape out with respect to final volume

Answer 1

Fraction of gas escaped $= 1-\frac{5}{7.5}=0.333$

Explanation:

According to Ideal Gas Law, $PV =nRT$

where P is pressure , V is volume ,n is no. of moles , R is gas constant  and T is temperature.

There is an open vessel thus pressure remains constant and there will be no change in the volume of vessel.

$\frac{V}{T} = constant$

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

$V_1 = 5l  \hspace{1cm} T_1=300k$

$V_2 = ?  \hspace{1cm} T_2=450k$

Equation became, $\frac{5}{300} =\frac{V_2}{450}$

$V_2=\frac{450\times5}{300}$

$V_2= 7.5l$

Thus, Fraction of gas escaped $= 1-\frac{5}{7.5}=0.333$