Question

A sample of 700 members has a mean 5.2 and variance 2.5. Find the 99% confidence interval for the mean.

Answer 1

Answer:

Step-by-step explanation:

What is that question

Answer 2

A sample of 700 members has a mean 5.2 and variance 2.5. The 99% confidence interval for the mean is 5.046 to 5.354

Step-by-step explanation:

Given

Sample size $n = 700$

Mean $\bar x=5.2$

Variance $\sigma^2=2.5$

Therefore,

Standard Deviation

$\sigma=\sqrt{2.5}=1.58$

We know that if mean, standard deviation and sample size is known, the confidence interval is given by

$\bar x\pmz*\frac{\sigma}{\sqrt{n}}$

Where the value of $z*$ for 99% confidence interval is 2.58

Thus, the interval is

$5.2\pm2.58\times\frac{1.58}{\sqrt{700}}$

$=5.2\pm\frac{4.08}{26.46}$

$=5.2\pm0.154$

$=5.046\text{ to }5.354$

Hope this answer is helpful.

Know More:

Q: A 95% confidence interval means 95% of all samples of size n would fall _____ our confidence interval.

Select one:

a. None of the choices

b. Within

c. Above

d. Outside

e. Below

Click Here: https://brainly.in/question/13773731

Q: A statistician calculates a 95% confidence interval for Mean when Standard Deviation is known. The confidence interval is Rs.18000 to Rs.22000, the amount of the sample mean is:

Click Here: https://brainly.in/question/2793453