Question

a sample of 80g of ferric oxide on reduction with give 42g iron.percentage​

Answer 1

Answer:

and the answer is 75%.

Explanation:

the balanced equation for the reaction is :

Fe2 O3 + 3C = 2Fe + 3CO

160 gm of Fe2 O3 gives 112 gm of Fe (iron)

80 gm of Fe2 O3 gives = 112/160*80 = 56 gm of Fe

56 gm of Fe formed from =80 gm of Fe2 O3

42 gm of Fe formed from = 80/56*42 = 60 gm of Fe2 O3

%percentage of Fe2 O3 = 60/80*100 = 75 % ..(Ans.)

this was the explanation but your question u asked was just not full so plzz check first before asking as I understood half of it the full question was (find the percentage of purity of sample )