Question

A sample of a gas has a mass of 1.92g at STP. what is the molar mass of the gas?

Answer 1

Answer:

Moles gas = pV / RT = 1 atm x 1.00 L / 0.0821 x 273 K =0.0446

Moles gas = pV / RT = 1 atm x 1.00 L / 0.0821 x 273 K =0.0446Molar mass = 1.92 g/ 0.0446 mol=43.0 g/mol

Moles gas = pV / RT = 1 atm x 1.00 L / 0.0821 x 273 K =0.0446Molar mass = 1.92 g/ 0.0446 mol=43.0 g/mol00

Explanation:

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