a sample of a gas occupies 10L at 120 degree Celsius at 1 atmosphere pressure. what volume of air will be expelled when it cooled to -23 degree Celsius at the same pressure
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Explanation:
T1 = 120C = 393K
T2 = -23C = 250K
V1 = 10L
Since pressure is same,
Applying Charles' law,
V1 / T1 = V2 / T2
10 / 393 = V2 / 263
V2 = 10/393*250
V2 = 6.36L
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