Question

A sample of a liquid has an initial volume of 1.5 L The volume is reduced by 0.2 mL, when the pressure increases by 140 kPz. What is the bulk modulus of the liquid?

Answer 1

Given :

- Intial volume of sample liquid = 1.5 L

- Volume reduced by = 0.2 mL = 0.2 × 10^-3 L

- Increment in pressure = 140 kPa = 140 × 10^3 Pa

To find :

• The bulk modulus of the liquid

Solution :

We know that,

Bulk modulus is given by formula

B = - ∆P / (∆V / V)

= - V × ∆P / ∆V

B = - 1.5 × 140 × 10^3 / (-0.2 × 10^-3)

= 15 × 14 × 10^6 / 0.2

= 15 × 7 × 10^6 / 0.1

B = 1.05 × 10^9 Pa

Answer 2

Answer:

1.05*10^9Pa

Explanation:

B=-1.50*140*10^3/0.2*10^-3

B=1.05*10^9Pa