Question

A sample of a mixture of gases contains 88g of CO, gas and 96g of O2 gas. Find out the mole fraction of the two gases in the mixture.​

Answer 1

Given mixture contains:

88g of CO gas

96g of O2 gas

To find:

Mole fraction of the two gases.

Solution:

No. of moles (n) = Given mass/Molar Mass

For CO,

n = 88/28 = 3.14 Moles

For O2,

n = 96/32 = 3 Moles

Mole fraction = Mole conc./Total moles

Mole fraction of CO

= 3.14/(3.14 + 3)

= 3.14/6.14

= 0.511

Mole Fraction of O2

= 3/(3.14 + 3)

= 3/6.14

= 0.488

Answer 2

Answer:

Explanation:

given

88g of co  ... 96g O2 gas

Ans :

given mass of o2 gas = 96 g ..  n ( O2) = 96 / 32 = 3

given mass of CO = 88g .......... n ( CO) = 88 / 28 ≈ 3

X ( of O2 ) = 3 / { (88/28 ) + 3 }

                = 3 / (3 + 3 )

                = 1/2

x ( of CO ) = 1 - 1/2

                 = 1/2