Question

A sample of a mixture of gases contains 88g of CO, gas and 96g of O2 gas. Find out the mole fraction of the two gases in the mixture.​

Answer 1

Answer:

ANSWER

no. of moles of nitrogen gas =

28

56

=2

no . of moles of carbon-dioxide gas =

44

44

=1

no. of moles of methane =

16

16

=1

Total no. of moles in the mixture = 4

Thus, mole fraction of methane =X

CH

4

=1:4

P

CH

4

=P.X

CH

4

X

CH

4

=

4

1

P

CH

4

=180 mm

Answer 2

Given mixture contains:

88g of CO gas

96g of O2 gas

To find:

Mole fraction of the two gases.

Solution:

No. of moles (n) = Given mass/Molar Mass

For CO,

n = 88/28 = 3.14 Moles

For O2,

n = 96/32 = 3 Moles

Mole fraction = Mole conc./Total moles

Mole fraction of CO

= 3.14/(3.14 + 3)

= 3.14/6.14

= 0.511

Mole Fraction of O2

= 3/(3.14 + 3)

= 3/6.14

= 0.488

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