Question

A sample of air occupies 1 dm3 at room temperature and pressure. What pressure is needed to compress it so that it occupies only 100 cm3 at that temperature

Answer 1

Answer:

Given data:

P1= 1 atm

V1= 1 dm3 which is equal to 1000cm3

P2=?

V2=100 cm3

solution

P1V1=P2V2

(1)(1000)=P2(100)

P2=1000÷100

P2= 10 atm

Answer 2

Answer:

7600mmHg or 10

Explanation:

P1V1=P2V2

760×1=P2×0.

P2=7600mmHg or 10 atm