Question

A sample of al has a mass 54g. What is the mass of the same number of mg

Answer 1

In this case, finding number of moles of sample of aluminium would help:

Number of moles = Given mass / Atomic mass

Using this formula; finding the number of moles of aluminium-

• Given mass = 54 g

• Atomic mass of aluminium = 27

So: 54/27 = 2 moles of Aluminium

Here, the mass of 2 moles of Magnesium would be:

• Number of moles = 2

• Atomic mass of Magnesium: 24

So: 24 × 2 = 48 grams of Magnesium (answer).

Answer 2

Answer:

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Mole $= \frac{given \: mass}{molar \: mass}$

Then, moles of aluminum $= \frac{54}{27}$$= 2$

According to question,

For 2 moles of magnesium it's mass is $2 × 24 = 48g$

Hence, the required mass for same number of magnesium atoms is 48g.

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