Question

A sample of aluminium has a mass of 54.0 g. What is the mass of the same number of magnesium
atoms? (At. wt. Al = 27. Mg=24)
(1) 12 g
(2) 24 g
(3) 48 g
(4) 96 g​

Answer 1

Explanation:

Weight of aluminium given =>54 g.

Number of moles of Aluminium =>54/27 =>2

1 mole of Aluminium has 6×10^23 particles then 2 moles of Aluminium should have 12×10^23 particles. 2 moles of any substance will have the same no. of particles so 2 moles of Magnesium weighs (24×2) gms => 48 gms. Hope it helps you.

Answer 2

Answer:

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Mole $= \frac{given \: mass}{molar \: mass}$

Then, moles of aluminum $= \frac{54}{27}$$= 2$

According to question,

For 2 moles of magnesium it's mass is $2 × 24 = 48g$

Hence, the required mass for same number of magnesium atoms is 48g.

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