Question

A sample of ammonia weighs 3.00g what mass of sulphur dioxide contains the same number of molecules as are in 3.00 ammonia?( given-at mass N-14, H-1, S-32,O-16)​

Answer 1

Answer:

Number of moles of ammonia in 3.00 g 3.00 17 mol

= 0.1764 mol

Molecular mass of SO3 = 1 x 32 u + 3 x 16 u = 80 u

1 mole of SO, weighs 80 g

0.1764 moles weigh = 80 x 0.1764 g

= 14.11 g

Explanation:

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Answer 2

Both compounds have the same number of molecules, hence the number of moles is the same.

For NH₃,

n = given mass/Molar mass = 3/17

For SO₂,

n = given mass/Molar mass = x/64  ...(ii) [we have to find the mass of SO₂]

Using (i) and (ii),

3/17 = x/64

⇒ x = 64*3/17

⇒ x = 11.3g (approx.)

∴ 11.3 g of SO₂ contains the same number of molecules as 3 g of ammonia.

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