Question

a sample of ammonium phosphate contains 3.18 moles of hydrogen atoms. find the no. of moles of oxygen atom

Answer 1

Ammonium Phosphate is $(NH_{4})_{3}PO_{4}$
Each atom contains 12 atoms of H and 4 atoms of O
Which means that for 12 moles of H, there are 4 moles of O
So, for 3.18 moles of H, we will be having 3.28 x 4/12 = 1.093333 moles of O atoms

Answer 2

$\Huge\blue{\mathfrak{\underline{\underline{answer}}}}$

$\large\red{\textbf{1.06 moles}}$

$\Huge\blue{\mathfrak{\underline{\underline{Solution}}}}$

→ 1 mole of (NH4)3PO4 will contain 12 mole H- atom

→ So, 3.18 mole of H-atom will be present in

→ 1/12 × 3.18 moles of (NH4)3PO4

= 0.265 moles of (NH4)3PO4

→ 1 mole of (NH4)3PO4 contains 4 moles of H-atom.

→ So, 0.265 (NH4)3PO4 will contain

→ 4×0.265 = 1.06 moles of oxygen atoms.