a sample of ammonium phosphate contains 3.18moles of hydrogen atom the number of moles of oxygen atom in the sample is
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Let's count individual atoms in (NH4)3PO4(NH4)3PO4
NHPO=3=12=1=4N=3H=12P=1O=4
From this,we come to know that 12 moles of Hydrogen correspond to 3 moles of Oxygen.
Let xx moles of Oxygen correspond to 3.18 moles of Hydrogen
∴x4∴x=3.1812=3.18×412=3.183=1.06moles
NHPO=3=12=1=4N=3H=12P=1O=4
From this,we come to know that 12 moles of Hydrogen correspond to 3 moles of Oxygen.
Let xx moles of Oxygen correspond to 3.18 moles of Hydrogen
∴x4∴x=3.1812=3.18×412=3.183=1.06moles
Answered by
2
→ 1 mole of (NH4)3PO4 will contain 12 mole H- atom
→ So, 3.18 mole of H-atom will be present in
→ 1/12 × 3.18 moles of (NH4)3PO4
= 0.265 moles of (NH4)3PO4
→ 1 mole of (NH4)3PO4 contains 4 moles of H-atom.
→ So, 0.265 (NH4)3PO4 will contain
→ 4×0.265 = 1.06 moles of oxygen atoms.
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