Question

A sample of an unknown substance has mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?

Answer 1

Answer : The specific heat of the substance is, $0.19J/gK$

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = heat required = 345.2 J

m = mass of unknown substance = 89.5 g

c = specific heat of the substance = ?

$\Delta T=\text{Change in temperature}$  

$T_{final}$ = final temperature = 305 K

$T_{initial}$ = initial temperature = 285 K

Now put all the given values in the above formula, we get the specific heat of the substance.

$345.2J=89.5g\times c\times (305-285)K$

$c=0.19J/gK$

Therefore, the specific heat of the substance is, $0.19J/gK$

Answer 2

Answer:

0.193

Explanation:

Don't round to the hundredths place.