Question

A sample of an unknown substance was found to contain 0.24 g of carbon, 0.040 g of hydrogen and 0.32 g of oxygen. The empirical formula of the unknown was d) CH20. a) C2h4O2. b) CH3O. C2H20.c)​

Answer 1

Explanation:

carbon- .24/12

hydrogen- .040/1

oxygen - .32/16

Answer 2

Answer:

Explanation:Mass of the given sample compound = 0.24g

Mass of boron in the given sample compound = 0.096g

Mass of oxygen in the given sample compound = 0.144g

% composition of compound = % of boron and % of oxygen

Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100

= 40%

Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100

= 60%