Question

A sample of bone in the form of a cylinder of cross-section of
area 1.5cm²is loaded on its upper end by a mass of 10 kg. By careful
measurement with a traveling microscope, the length of the
cylindrical sample is observed to decrease by o.oo65%.calaculate
the value of Yaung modulus for the specimen.

Answer 1

Answer:

is a measure of the total polarizability of a mole of a substance and is dependent on the temperature, the index of refraction, and the pressure. is the mean polarizability of a molecule. are m3 mol−1.

Explanation:

Answer 2

Answer:

The value of Young modulus for the specimen is 1.005 × 10¹⁰ Pa.

Explanation:

Given,

Area of a cross-section of the cylindrical bone sample, A = 1.5 cm²

Convert cm² into m²

• 1 cm² = 10⁻⁴ m²
• 1.5 cm² = 1.5 × 10⁻⁴ m²

Mass of the bone sample, m = 10 Kg

The length of the cylindrical bone sample decreased by, L = 0.0065%

Therefore, extension per unit length, $\frac{dL}{L}$ = $\frac{0.0065}{100}$ = 6.5 × 10⁻⁵

The value of young modulus, Y =?

As we know,

• Young modulus can be calculated by the equation given below:
• $Y = \frac{F/A}{dL/L}$

Here,

• Y = Young modulus of the specimen
• F = Force observed
• A = Area of cross-section
• $\frac{dL}{L}$ = Extension per unit length

As we know,

• Force = mass × acceleration due to gravity
• $F = m\times g$
• F = 10 × 9.8 = 98 N

Now, after putting all the values in the equation, we get:

• $Y = \frac{98/1.5\times 10^{-4} }{6.5\times 10^{-5} }$
• $Y = \frac{65.33\times 10^{4} }{6.5\times 10^{-5} }$
• Y = 1.005 × 10¹⁰ Pa

Therefore, the value of young modulus, Y = 1.005 × 10¹⁰ Pa.