A sample of C12H22O11 , that contains 72g of carbon also contains how many grams of oxygen ?
answer - 88g
someone please give the correct explanation
wrong answers will be reported
Answers
Answer:
Answer is: 88g
Explanation:
Given: The sample of (C_{12} H_{22} O_{11} 72 g of carbon.
To find: Mass of oxygen contain in (C_{12} H_{22} O_{11}
Solution: In the given sample,
1 mole of (C_{12} H_{22} O_{11} contains 12 carbon atoms.
This means that 1 mole of (C_{12} H_{22} O_{11} contains 144g of carbon atom (because it contains 12 carbon atoms and mass of 1 carbon atom is 12 g).
Similarly, 1 mole of (C_{12} H_{22} O_{11} contains 176 g of oxygen atom (because it contains 11 oxygen atoms and mass of 1 oxygen atom is 16g).
Now,
144g carbon compound has = 176 g of oxygen atom
so, 1 g of carbon compound has = \frac{176}{144} =1.22g oxygen atoms
and 72 g of carbon compound has = 1.22×72g = 88g (approximately)
Therefore, the correct answer is 88g.
Answer:
Similarly, 1 mole of (C_{12} H_{22} O_{11} contains 176 g of oxygen atom (because it contains 11 oxygen atoms and mass of 1 oxygen atom is 16g). Therefore, the correct answer is 88g.