a sample of cabr2 and nabr contains 2.4×10²³ atom of ca and 6.6×10²³ atom of br . what is the mass of nabr in the given sample?
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Answer: Moles of Na, n
Na
=
M
w
=
23
2.04
=0.088
Moles of C, n
C
=
N
A
N
=
6.022×10
23
2.65×10
22
=0.044
Moles of O, n
O
=0.132
Now,
n
Na
:n
C
:n
O
=0.088:0.044:0.132=2:1:3
The empirical formula of the compound =Na
2
CO
3
Explanation:
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