Question

A sample of CaCO3 contains 67.2 litre of oxygen gas at
STP. The mass of CaCO3?
(a) 100g
$)
(6) 300g
(c) 400g
(8200g​

Answer 1

Explanation:

Your answer is option (c) ...ok...

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Answer 2

Explanation:

Therefore 67.2L = 67.2/22.4 = 3 mol O2. Answer: 200g CacO3 will contain 67.2L O2 at STP.

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