Question

A sample of Caco3, has Ca = 40%, C = 12% and Q = 48%. If law of constant proportions is true, the
weight of calcium in 4g of sample of Caco3, obtained from another source will be​

Answer 1

According to law of definite proportions, in a chemical substance, the elements are always present in definite proportions by mass.

Given data:

Percentage of Ca present in CaCO3 – 40%

Percentage of C present in CaCO3 - 12%

Percentage of O present in CaCO3 - 48%

This means 100g of calcium carbonate contains 40g of Ca, 12g of C and 48g of O.

Similarly, 2g of Calcium carbonate contains 40% calcium , 12% carbon and 48 % oxygen by mass.

Let us find the masses of Ca, C and O present in 2g of CaCO3.

Mass of Calcium present in 2g of CaCO3 = 40/100 X2 = 0.8g

Mass of Carbon present in 2g of CaCO3 = 12/100 X 2 = 0.24g

Mass of Oxygen present in 2g of CaCO3 = 48/12 X 2 = 0.96g.

Answer 2

Answer:

1.6g

Explanation:

acc to law of definite proportion