Question

a sample of CaCO3 is introduced into a sealed container of volume 0.654 L heated to 1000 K until equilibrium is reached. The equilibrium constant for the reaction CaCO3 gives CaO and CO2 is 3.9×10^-2 atm at this temperature. Calculate the mass of CaO present at equilibrium​

Answer 1

Answer:

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Answer 2

Answer:

The equilibrium constant expression is K=P

CO

2 =4×10

2

atm.

The number of moles of carbon dioxide can be calculated from ideal gas equation.

n= RT

PV = 0.0821×1000

4×10

2

×0.821

=4

The number of moles of CaO is equal to the number of moles of carbon dioxide. it is equal to 4 moles.

The molar mass of CaO is 56 g/mol.

The mass of CaO present is 4×56=224 g

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