a sample of caco3 of 90 kg contains 45 kgs of caco3 then find the percentage of purity of the sample
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Answer:
In 100 g CaCO
3
, 40 g Ca is present.
In 4 g CaCO
3
, Let x g Ca be present
4
x
=
100
40
⟹x=1.6 g
Explanation:
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