Chemistry, asked by Chaithanya3024, 10 months ago

A sample of calcium carbonate (CaCO3) has the following
percentage composition: Ca = 40%; C = 12%; 0 = 48%, If
the law of constant proportions is true, then the weight of
calcium in 4g of a sample of calcium carbonate from
another source will be in g)​

Answers

Answered by Anonymous
2

Answer:

Then the weight of calcium in 4 g of a sample of calcium carbonate obtained from another source will be. ... Ca=40%,C =12%,O=48% If the law of constant proportions is true.

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