Question

. A sample of Calcium carbonate has Ca = 40%, C = 12% and O = 48%. If the law of constant proportions is true, then the mass of Ca in 4g of a sample of Calcium carbonate from another source will be:

Answer 1

Answer:This means 100g of calcium carbonate contains 40g of Ca, 12g of C and 48g of O. Similarly, 2g of Calcium carbonate contains 40% calcium , 12% carbon and 48 % oxygen by mass. Let us find the masses of Ca, C and O present in 2g of CaCO3. Mass of Oxygen present in 2g of CaCO3 = 48/12 X 2 = 0.96g.