A sample of carbon dioxide gas at a pressure of 1.07 atm and a temperature of 166 °C, occupies a volume of 686 mL. If the gas is heated at constant pressure until its volume is 913 mL, the temperature of the gas sample will be ? °C.
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P₁ = 1.07 atm
T₁ = 166°C = 166 + 273 = 439 K
V₁ = 686 mL
P₂ = 1.07 atm
T₂ = ?
V₂ = 913 mL
According to gas law equation,
( P₁ V₁ ) / T₁ = ( P₂ V₂ ) / T₂
⇒ T₂ = T₁ ( P₂ V₂ ) / ( P₁ V₁ )
= 439 * 1.07 * 686 / 1.07 * 913
= 439 * 686 / 913
= 329.85 K
= (329.85 - 273 )°C
= 56.85 °C
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