A sample of carbon dioxide occupies 1.65L at -20.0°c and 20.0 psi. if the volume of the gas is 2.65L at 35.0 psi, what is the celsius temperature?
Answers
Answer:
The new volume is 25mL .
Explanation:
From the above question,
From the above question a sample of carbon dioxide occupies 1.65L at -20.0°c,
Initial volume of the gas = 1.65 mL
Initial pressure = 20 atm
Final pressure = 20 atm
To find he volume of the gas is 2.65L at 35.0 psi :
According to Boyle's Law, we know that :
P₁V₁ = P₂V₂ [ T is constant]
Where :-
P₁ is the initial pressure.
V₁ is the initial volume of the gas.
P₂ is the final pressure.
V₂ is the final volume.
Substituting values, we get :-
20(50) = 40(V₂)
1000 = 40V₂
V₂ = 1000/40
V₂ = 25 mL
Boyle's Law is a gas law which states that the pressure exerted by a gas of given mass, at a constant temperature is inversely proportional to volume occupied by it.
Thus, the new volume is 25mL .
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