A sample of Cl2 gas occupies 8.50 L at 80 °C and 740 mmHg. What volume will the Cl2 occupy at STP? *
Answers
Explanation:
GIVEN
- Volume = 8.50 L
- Temperature = 80°C or 353 K
- Pressure = 740 mmHg
To find
- Volume occpied by Cl₂ at STP
Assumption
- V1 = 8.50 L
- T1 = 353 k
- T2 = 302.5 k
(P1 × V1/T1) = (P2 × V2/T2)
V1/T1 = V2/T2
V2 = (V1 × T2)/T1
V2 = (8.50 × 302.5) / 353
V2 = 7.28 L
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Given: Volume of Cl₂ gas, V₁ = 8.50L
Temperature, T₁ = 80 ⁰C
Pressure exerted by Cl₂ gas ,P1 = 740 mmHg
To Find: Volume occupied by Cl₂ gas at STP, V2.
Solution:
To calculate V₂, the formula used:
- P₁V₁ / T₁ = P₂ V₂ / T₂
Here, P₂, is the pressure at gas at STP = 760mmHg
T₂ is the temperature at STP = 273.15K
Applying the above formula:
740 x 8.50 / 80 = 760 x V₂ / 273.15
First convert 80⁰C into K:
80⁰C = 80 + 273.15
= 353.15 K
Convert 8.50 L in ml:
1 L = 1000ml
8.50 L = 8.50x 1000
= 8500 ml
Putting these values in the formula for V₂:
740 x 8500 / 353.15 = 760 x V₂ / 273.15
6290000/ 353.15 = 760 x V₂ / 273.15
1.78 x 10000 = 760 x V₂ / 273.15
1.78 X 10000 x 273.15 = 760 x V₂
17800 x 273.15 / 760 = V₂
4862070 / 760 = V₂
6397.5 = V₂
V₂ = 6397.5 ml
Hence, the volume occupied by the Cl₂ gas is 6397.5 mL.