Question

A sample of clay contains 50% silica and 10% water. The sample is partially dried by which it loses 8 gm
water. If the percentage of silica in the partially dried clay is 52, calculate the percentage of water in the
partially dried clay?

Answer 1

Answer:11th

Chemistry

Some Basic Concepts of Chemistry

Atomic and Molecular Masses

A sample of clay contains 5...

CHEMISTRY

A sample of clay contains 50% silica and 10% water. The sample is partially dried by which it loses 8 g water. If the percentage of silica in the partially dried clay is 52, what is the percentage of water in the partially dried clay?

MEDIUM

Study later

ANSWER

Let weight of clay is x gm

∴  Weight of silica =  

100

50

​  

×x

                                =0.5 x gm

∴  Weight of water =  

100

10

​  

×x=0.1 x gm

Now,

8 gm water is reduced

∴  weight of clay =(x−8) gm

Weight of silica =  

100

52

​  

×(x−8) gm

=(0.52 x−4.16) gm

Now, Weight of silica in both case are equal.

∴ 0.5 x=0.52 x−4.16

0.02 x=4.16

∴ x=208 gm = weight of clay initially.

∴  weight of water =0.1 x=20.8 gm

Now, 8 g water is reduced.

∴  Weight of water =20.8−8 x=12.8 gm

Weight of clay =208−8 gm=200 gm

∴ % of water =  

200

12.8

​  

×100=6.4%

Explanation:

pls mark me the brainliest