A sample of copper sulphate pentahydrate Consists of 3.782 grams of cu. How many grams of oxygen are there in the sample,
Answers
Answered by
0
Answer:
Molar mass of CuSO
4
.5H
2
O=1Cu+1S+4O+10H+5O=63.5+32.1+4×16+10×1+5×16=249.6g
Oxygen and copper will be present in 9:1 molar ratio always.
63.5g of Cu
144g of O
=
3.782g of Cu
x g of O
Hence, grams of oxygen in this sample=
63.5
144×3.782
=8.576gram
Hence, the answer is D.
Answered by
0
Answer:
4g
Explanation:
mass of Cu in CuSO4.5H2O = 63.5g
moles of Cu = 3.782/ 63.5 = 0.05 (approx)
no of atom of O in CuSO4.5H20 = 5
No of mole =0..5× 0.5 = 0.25
MASS OF O = 0.25 × 16 = 4gram
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