Question

A sample of CxOy having 3×10^19 molecules is weighing 3.4 mg . then the value of c and y is​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given A sample of CxOy having 3×10^19 molecules is weighing 3.4 mg . then the value of x and y is

• So number of molecules = 3 x 10^19
•     So Moles = Number of molecules / Avagadro constant NA
•             Moles = 3 x 10^19 / 6 x 10^23
•                        = 0.5 x 10^-4  
•                        = 5 x 10^-5 mole.
• Now moles = mass in gm / molar mass
•            5 x 10^-5 = 3.4 x 10^-3 / m
•             Or m = 68 gm / mole
•     Now molecular weight of  CxOy will be
•                        12 x + 16 y = 68
•             By trial and error method we get
•                          x = 3 and y = 2
• So we get the compound as C3O2 and so we get 3,2

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https://brainly.in/question/941298