A sample of dolomite contains 45% of CaCO3, 40% of MgCO3 and 15% less calculate the mass of sulphuric acid of 30% strength required to react completely with 10 g of the sample
Please attach a picture as it is difficult to understand when typed.
Answers
Answer:
Explanation:
As we know that clay which is a non-reactant with H2SO4.
So from the equation we can get to know that the mass peecentage of the given data can be calculated as follow.
CaCO3 + H2SO4 -> CaSO4 + H2O + CO2
Since, 10g of the sample is given,
(45% of 10 g) / (100.0875 g CaCO3) x (1 mol H2SO4 / 1 mol CaCO3) =
0.04496 mol H2SO4 to react with the CaCO3 in the reaction for mixing up with MgCO3 to give dolomite
MgCO3 + H2SO4 -> MgSO4 + H2O + CO2
(40% of 10 g) / (84.31413 g MgCO3) x (1 mol H2SO4 / 1 mol MgCO3) =
0.04744 mol H2SO4 will react with the MgCO3 to give the dolomite by reacting with CaCO3.
(0.04496 mol + 0.04744 mol) x (98.0791 g H2SO4/mol) / (0.30) = 30 g 30% H2SO4 will form of 30% strength from the above datas.
Answer:
Solution given in the pictures
