a sample of drinking water was found to be severely contaminated with chloroform, CHCl3 , supposed to be carcinogenic in nature. The level of contamination was 15 ppm (by mass).
i) Express this in percent by mass .
ii) Determine the molality of chloroform in the water sample .
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Answer:
MOLAR MASS OF CHCL3 = 119.5
CONTAMINATION = 15ppm
MEANS 15g OF CHCL3 IS PRESENT IN 10^6 g OF SOLUTION
MASS% = (MASS OF SOLUTE /MASS OF SOLUTION) *100
MASS% = 15/10^6 *100
SO MASS% = 1.5*10^-3
MOLALITY = NO OF MOLES OF SOLUTE/MASS OOF SOLVENT (IN KG)
MASS OF SOLVENT = 10^6 - 15 (SOLUTION = SOLUTE+SOLVENT)
MOLES OF SOLUTE = 15/119.5
HENCE--> MOLALITY = 15/119.5 X1000/10^6
SO MOLALITY = 1.255 x 10^-4
HOPE THE SOLUTION WAS HELPFUL 2 U....
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