Question

A sample of drinking water was found to be severely contaminated with chloroform,
CHCI3 supposed to be carcinogenic in nature. The level of contamination was 15
ppm (by mass). Determine the molality of chloroform in the water sample. "Don't copy from anywhere otherwise I will report your answer". ​

Answer 1

Answer:

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15 ppm corresponds to 15 g chloroform in 1000,000 g of solution.

(i) Percent by mass = Mass of solution

Mass of chloroform ×100

Percent by mass = 1000,00015 ×100=1.5×10 −3 %

(ii) Molality = Molar mass of chloroform ×(Mass of solution−mass of chloroform)

Mass of chloroform ×1000 (all masses in g)

Molality = 119.5×(1000,000−15)15 ×1000=1.255×10−4 m.

lai bhai trra ans samaj lai ab na report kariyo

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