A sample of fexo contains one fe(iii) for every three fe(ii) then the value of x is
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Step-by-step explanation:
Consider 1 mole of iron.
Amount of fe(ii) will be 1/4 mol
Amount of fe(ii) will be 3/4 mol
Total +ve charge = 1/4 (3) + 3/4 (2) = 9/4 mol
if x is number of o2 atoms, then amount of -ve charge is 2x.
Total +ve charges = Total -ve charges
9/4 mol = 2x
hence x = 9/8 mol
hence composition is Fe₈O₉.
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