Question

A sample of fexo contains one fe(iii) for every three fe(ii) then the value of x is

Answer 1

Answer:

Step-by-step explanation:

Consider 1 mole of iron.

Amount of fe(ii) will be 1/4 mol

Amount of fe(ii) will be 3/4 mol

Total +ve charge = 1/4 (3) + 3/4 (2) = 9/4 mol

if x is number of o2 atoms, then amount of -ve charge is 2x.

Total +ve charges = Total -ve charges

9/4 mol = 2x

hence x = 9/8 mol

hence composition is Fe₈O₉.