Question

A sample of fossilized wood has a carbon -14 decay rate of 6.00 disintegration per minute per gram . Determine the age of the sample . The decay rate of carbon -14 is fresh wood today is 13.6 count's per minute per gram and the decay constant of carbon -14 is 3.84 *10^-125 per sec​

Answer 1

Answer:

Hope this answer will be helpful for you.❤❤❤❤❤❤❤❤

Explanation:

A chemist determines that a sample of petrified wood has a carbon-14 decay rate of 6.00 counts per minute per gram. What is the age of the piece of wood in years? The decay rate of carbon-14 in fresh wood today is 13.6 counts per minute per gram, and the half life of carbon-14 is 5730 years.

Solution:

1) Determine decimal fraction of C-14 remaining:

6.00 / 13.6 = 0.4411765

2) Determine how many half-lives have elapsed:

(1/2)n = 0.4411765

n log 0.5 = log 0.4411765

n = 1.18057

3) Determine length of time elapsed:

5730 yr x 1.18057 = 6765 yr

Answer 2

Explanation:

this is your answer

hope it will help u

thank you