Question

a sample of gas at 0 degree Celsius and 1 ATM pressure occupies 300 what change in temperature is necessary to adjust the pressure of the gas 21.5 ATM after it has been transferred to 200 litre container​

Answer 1

Answer:

The gas should be kept at -248 degrees C.

Explanation:

Use Charles Law. Temperature and Volume are directly related using degrees Kelvin. ( if the pressure and number of molecules are kept constant.

V

1

T

1

=

V

2

T

2

V

1

=

37.5

l

T

1

=

35

+

273

=

308

degrees K

V

2

=

3.0

l

# T_2 = unknown

Substituting these numbers into the equation gives

37.5

308

=

3.0

T

2

multiplying across gives

T

2

=

308

×

3.0

37.5

Which gives

# T_2 = 24.6 degrees K

Subtract 273 to find degrees C.

24.6

−

273

=

−

248

degrees C. ( to three significant digits.)

Answer 2

Given

P1=1atm

V1 = 2.5 litre

T1 = 273K

P2 = 1.5 atm

V2 = 2.0 litre

T2 = ?

We know that

P1V1T1=P2V2T2

1×2.5273=1.5×2.0T2

⇒T2=327.6K

⇒or54.6∘C

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