Question

A sample of gas at 1.20 atm and 27 ℃ is heated at constant pressure to 57 ℃. Its final volume is 4.75L What was its original volume?

Answer 1

Answer:

V1=4.3181L

Explanation:

using combined gas equation

p1v1/t1=p2v2/t2

t should be in kelvin

k=c°+273

t1=27+273=300k

t2=57+273=330k

v1=?

v2=4.75L

p1=p2=1.2atm

p1v1/t1=p2v2/t2

1.2×v1/300=1.2×4.75/330

v1=1.2×4.75/330×300/1.2

v1=4.3181L