Question

A sample of gas contains N1 molecules and the total kinetic energy at -123 oC is E1 ergs, Another sample of gas at 27 oC has total kinetic energy as 2E1. Assuming gases to be ideal, the number of gas molecules in the second sample will be:- Kindly answer sir/mam.


a) N1
b) N1/2
c) 2N1
d) 4N1

Answer 1

Total kinetic energy of a gas sample is proportional to the temperature of the gas molecules and the number of molecules present in the sample. The exact equation is,

KE = (3/2×K×T)×N

where K is the Boltzman's constant and T is the temperature on the absolute scale. N represents the number of molecules of gas present in the sample.

So, in the first case, KE = 3/2×K×150×N₁

In the second case, KE = 3/2×K×300×N₂

(KE)₂/(KE)₁ = 2 → 2N₂/N₁ = 2 → N₂ = N₁

Answer 2

Hope it will help u

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