A sample of gas has a pressure of 700 mmHg and 300 Kelvin. At what temperature would the pressure be if the pressure is lowered to 600 mmHg? *
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Answer:
Given,
Pressure (P1) = 700 mm of Hg
Temperature (T1) = 300 K
Pressure (P2) = 600 mm of Hg
According to Regnault's Pressure Law,
P1/T1 = P2/T2
700/300 = 600/T2
700T2/300 = 600
T2 = 600*300/700
The Temperature would be 257.142 K or, -15.857°C.
I hope this helps.
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