Question

A sample of gas mixture contains 2.2 g CO,(g),
4.6 g NO,(g) and 4.8 g 02 (g). The number of oxygen
atoms present in the sample is (Assume gases are
non-reaction)​

Answer 1

Explanation:

CO+NO=CN+O2

28g of CO+30g of NO=36g of CN+32g of O2

32g of O2=2 atoms of oxygen

4.8gofO2=x

x=4.8×2/32

x=0.3atoms of O2