A sample of gas occupies 100 ml at 27 C and 740 mm pressure. what will be the temp of gas when its volume is changed to 80 ml at 740 mm pressure
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take eq. P1V1 = P2V2
T1 T2
here, P1=740mm V1 = 100ml ⇒ 100/1000 liter ⇒ 0.1 L
T1 = 27 c ⇒ 27 + 273 = 300 K
P2 = 740 mm V2 = 0.08 L T2 = X
put value in eq.
⇒ 740 × 0.1 = 740 × 0.08
300 x
⇒ X = 740 ×0.08 ×300
740 × 0.1
⇒ X = 240 K
T2 = 240 K
T1 T2
here, P1=740mm V1 = 100ml ⇒ 100/1000 liter ⇒ 0.1 L
T1 = 27 c ⇒ 27 + 273 = 300 K
P2 = 740 mm V2 = 0.08 L T2 = X
put value in eq.
⇒ 740 × 0.1 = 740 × 0.08
300 x
⇒ X = 740 ×0.08 ×300
740 × 0.1
⇒ X = 240 K
T2 = 240 K
bhalaraneha:
welcome
if ot helps u mark me best.. :)
pl can youtell it to me in celcius
it's -33.15 C > K = 273 - C
Thanks a lot
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