Question

A sample of gas occupies 600ml at 27℃ and 1 atm. What will be the volume at 127℃ if the pressure is kept constant ?

Answer 1

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v1 = 600 ml

t1 = 27℃ = 300k

p1 = 1 atm

and ,,,,,,,

v2 = ?

t2 = 127℃= 400k

p2 = 1 atm

now , Applying charles law ....

$\frac{p1v1}{t1} = \frac{p2v2}{t2}$

$\frac{600}{300} = \frac{x}{400}$

$2 = \frac{x}{400}$

$x = 800 \: ml$

$hope \: it \: helps$

$<b > prabhudutt$

Answer 2

✹QUESTION.



A sample of gas occupies 600ml at 27℃ and 1 atm. What will be the volume at 127℃ if the pressure is kept constant ?





✹ANSWER






✦FORMULA USED.


$\frac{v(1)}{t(1)} = \frac{v(2)}{t(2)}$






✦EXPLANATION OF FORMULA.



This is a charle's law .



☞Charle's Law .

According to charle's law volume of an ideal gas at constant pressure is directly proportional to the absolute temperature.




✦ NOW SOLUTION.



✦GIVEN

V(1) = 600ml

V(2)=?

T(1)=27°c



☞(In Kelvin.

T(1)=27°+273°
=300K)




T(2)=127°



☞(In Kelvin .

T(2)=127°+273°

=400°K



✦NOW. PUT THIS ALL VALUE IN FORMULA



$\frac{v(1)}{t(1) } = \frac{v(2)}{t(2)}$




$= > v(2) = \frac{v(1)}{t(1)} \times t(2)$




$= v(2) = \frac{600ml}{300k} \times 400k$




$v(2) = 200ml \times 4$




$v(2) = 800ml$





✦HENCE

The volume of sample of a gas is 800ml at 127°c (400k) temperature and at a constant pressure .