A sample of gas occupies a volume of 120.0 ml at a pressure of 0.75 atm and a
temperature of 22 degree Celsius. What will the volume be at a pressure of 125 atm
and a temperature of 70 degree Celsius?
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Answer:
0.83 ml
Explanation:
P1=0.75 atm
T1= 22 C= 22+273 K= 295K
V1= 120ml = 0.12L
n=?
P1V1=nRT1
0.75×0.12=n ×0.0821×295
0.09= n×24.2195
n= 0.09÷24.2195
n= 0.00371 moles
moles will remain same after pressure and temperature change
P2=125 atm
n=0.00371
T2= 70 C= 343 K
V2 =?
P2V2=nRT2
125×V2=0.00371×0.0821× 343
125×V2=0.1044
V2= 0.1044/125
V2 = 0.00083 L
V2= 0.83 ml
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