Question

A sample of gas occupies a volume of 2.74L at 0.9 atm and 27oC. What will be the
volume at 0.75 atm and 15oC?

Answer 1

Answer:

Given:-

\sf{V_{1}=2.74\;dm^{3}}

\sf{P_{1}=0.9\;bar}

\sf{T_{1}=27^{\circ}C}

\sf{V_{2}=?}

\sf{P_{2}=0.75\;bar}

\sf{T_{2}=15^{\circ}C}

\sf{Substituting\;values\;in\;the\;equation,}

\sf{\dfrac{P_{1}V_{1}}{T_{1}}=\dfrac{P_{2}V_{2}}{T_{2}}}

\sf{We\;get:}

\sf{\dfrac{0.9.(2.74)}{27} =\dfrac{1.75V_{2}}{15}}

\large{\sf{V_{2}=0.122\;dm^{3}}}

{\bf{Hope\;it\;helps\;you!}}

Answer 2

Answer:

Explanation:

combined gas eqn

(P1V1) / T1 = (P2V2)/T2

(0.9 x 2.74) / (27+273) =  (0.75 x V2) / (15+273)

0.00822 = 0.0026 V2

V2 = 3.16 L