A sample of gas occupies a volume of 2.74L at 0.9 atm and 27oC. What will be the
volume at 0.75 atm and 15oC?
Answers
Answered by
0
Answer:
Given:-
\sf{V_{1}=2.74\;dm^{3}}
\sf{P_{1}=0.9\;bar}
\sf{T_{1}=27^{\circ}C}
\sf{V_{2}=?}
\sf{P_{2}=0.75\;bar}
\sf{T_{2}=15^{\circ}C}
\sf{Substituting\;values\;in\;the\;equation,}
\sf{\dfrac{P_{1}V_{1}}{T_{1}}=\dfrac{P_{2}V_{2}}{T_{2}}}
\sf{We\;get:}
\sf{\dfrac{0.9.(2.74)}{27} =\dfrac{1.75V_{2}}{15}}
\large{\sf{V_{2}=0.122\;dm^{3}}}
{\bf{Hope\;it\;helps\;you!}}
Answered by
3
Answer:
Explanation:
combined gas eqn
(P1V1) / T1 = (P2V2)/T2
(0.9 x 2.74) / (27+273) = (0.75 x V2) / (15+273)
0.00822 = 0.0026 V2
V2 = 3.16 L
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