a sample of h2so4(density 1.28g/cm^3) is 68% by mass. calculate the volume of this sample which should be mixed with water to prepare 500 cm^3 of seminormal solution
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3
Answer:
Given that,
Density of acid soln = 1.8 g/ mL.
1000 mL volume will weight 1800g.
Mass of H
2
SO
4
present =1800×
100
90
=1620g
Number of mole of H
2
SO
4
=
molar mass
actual mass
=
98
1620
=16.53 mol
Thus molarity of stock solution is 16.53 M.
To prepare 1000 mL of 0.2 M solution,
M
1
V
1
=M
2
V
2
16.53×x=0.2×1000
x=
16.53
200
x=12.099 ml
x=12.1 ml
Explanation:
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2
Answer:
ਦਬੈਬਢਯਝਢਤਸ਼ਤਦਤਸ਼ਤਦਸਢਤਦਸ਼ਤਤਦਸ਼ਤਲਤਸ਼ਢ
Explanation:
ਦਮਸ਼ਤਤਰੈਤਧਢਸਢਰਢਸ਼ ਸ਼ਢਦਢ ਝਢਰਢ ਸ਼ਢ. ਦਢ ਦਢਰਸ਼ਢ ਚ ਝਢਰਢਸ਼ਚ ਡਝਚ ਘਝ ਢਝਢ ਘਦਘ ਢਸ਼ਡਘ. ਢਢਥਢਝਡ ਡਯਘ
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