Chemistry, asked by prem1695, 10 hours ago

a sample of h2so4(density 1.28g/cm^3) is 68% by mass. calculate the volume of this sample which should be mixed with water to prepare 500 cm^3 of seminormal solution​

Answers

Answered by lohitjinaga
3

Answer:

Given that,

Density of acid soln = 1.8 g/ mL.

1000 mL volume will weight 1800g.

Mass of H

2

SO

4

present =1800×

100

90

=1620g

Number of mole of H

2

SO

4

=

molar mass

actual mass

=

98

1620

=16.53 mol

Thus molarity of stock solution is 16.53 M.

To prepare 1000 mL of 0.2 M solution,

M

1

V

1

=M

2

V

2

16.53×x=0.2×1000

x=

16.53

200

x=12.099 ml

x=12.1 ml

Explanation:

</p><p></p><p>\huge \pink{} \red {l} \green {o} \blue {h} \orange {it}

Answered by swamiprachi368
2

Answer:

ਦਬੈਬਢਯਝਢਤਸ਼ਤਦਤਸ਼ਤਦਸਢਤਦਸ਼ਤਤਦਸ਼ਤਲਤਸ਼ਢ

Explanation:

ਦਮਸ਼ਤਤਰੈਤਧਢਸਢਰਢਸ਼ ਸ਼ਢਦਢ ਝਢਰਢ ਸ਼ਢ. ਦਢ ਦਢਰਸ਼ਢ ਚ ਝਢਰਢਸ਼ਚ ਡਝਚ ਘਝ ਢਝਢ ਘਦਘ ਢਸ਼ਡਘ. ਢਢਥਢਝਡ ਡਯਘ

ਦਡਝਦਡੈਡਦਡਝਡਦਡ

Similar questions