Question

A sample of hard water is found to contain 50 mg of CaSO4 in 12 kg of the sample.Calculate the hardness of the sample in terms of ppm of CaSO4.​

Answer 1

Answer:

38mg

Explanation:

given

Hard water is found to contain=50mg

CaSo4 in the sample = 12kg

to find

The sample in terms of ppm=?x

method

50+x=12

x=50- 12

x=38mg

answer 38mg

Answer 2

Answer:

4.167ppm of CaSO4

Explanation:

mass of solute=50 mg=50×10^-6 kg

mass of solution=12 kg

hardness of sample in ppm=

mass of solute/mass of solution

=

$50 \times 10 { }^{ - 6} \times 10 {}^{6} \div 12$

=4.167 ppm

Hope it helps...