A sample of Helium has a mass of 12g. What is the mass
of the same number of Oxygen atoms as Helium atoms
present in given sample ?
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Answer:
48 grams
Explanation:
Helium is a diatomic species, if one atom we’ll have atomic weight as 4g , then two will have weight 8g.
In question Helium
12/8 * Avogadro Constant = 3/2 Avogadro Constant
Weight of oxygen = 32(diatomic)
Oxygen and helium has same weight so ,
=>3/2* Avogadro Constant = X/32 * Avogadro Constant
=> 3/2 = X/32
=> X = 48
=> Hence 48g of oxygen will be present in the given compound.
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