A sample of helium has a volume of 500 cm^3 at 373 K. Calculate the temperature at which the volume will become 260 cm^3 keeping pressure constant.
Answers
Answered by
39
V1/T1 =V2/T2
500/373=260/T2
T2=(260×373)/500
=193.96 K
500/373=260/T2
T2=(260×373)/500
=193.96 K
Answered by
30
V1= 500 cm^3
T1=373 K
V2=260 cm^3
T2= ?
{Pressure is constant}
According to Charle's Law
{It states that at constant pressure and fixed mass of gas, volume is directly proportional to absolute temperature.This is also known as Temperature and Volume relationship.}
V1/T1 = V2/T2
500/373 = 260/T2
T2 = (260 X 373)/500
T2 = 96980/500
T2 =193.96 K
The temperature at which the volume will become 260cm^3 is 193.96 K
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