A sample of hydrogen at 47°C exerts a pressure of .329 atm. The gas is heated to 77°C at constant volume. What will its new pressure be?
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Since the gas is being heated only and the volume is not changing, therefore, n and V are constant and therefore we can say:
P
T
=
k
where
k
=
n
R
V
is a constant value that does not change during the process.
Thus,
P
1
T
1
=
P
2
T
2
This is called Gay-Lussac law.
⇒
P
2
=
P
1
T
1
×
T
2
⇒
P
2
=
0.329
a
t
m
320
K
×
350
K
=
0.360
a
t
m
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